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- 4 9π 2 4 β 3π
5 β 3π 2π 1 7π - Compute
a 2 2A I - Simplify 2 β
3 4 β 3 β β 27 - Re-Express 2I
and I - 2 I 1 3I
Solution - Complex Number
Quadrant - 4 I 2
8I - Rotatin Transformation
of Vector - 4 5I Z
1 I - Z 1 Isinx 1 Isinx Then
Modulus Z - I 6 I 7 I 8
I 9 I 2 I 3 - Product of
1 4I and 2 3I - 5.3I
- 5 Pi by Vy
4 ZZ2 - Simply 2 3I 4.
Use Caltech - Find the Conjugate of 3
2I
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